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Accueil → WINDEV 2024 → [WD18] Need help with regular expression
[WD18] Need help with regular expression
Débuté par guest, 15 avr. 2014 23:13 - 3 réponses
#1
Posté le 15 avril 2014 - 23:13
Hi,

To check a password strength I want to use this regular expression

"^.*(?=.{8,})(?=.*[a-z])(?=.*[A-Z])(?=.*[\W])(?=.*[\d]).*$"

But the MatchRegularExpression always return false ?

The rules would be:
* Min length 8
* At least 1 Capital letter
* At least 1 lower case letter
* At least 1 symbol
* At least 1 digit

When I use the following site https://www.debuggex.com to test the Regular expression it matches OK when I use a test string of "fnLny1sd+"

Any idea why Windev returns false every time ?

Thanks
Danny
[attachment 882 regex.png]
#2
Posté le 16 avril 2014 - 03:47
I have no idea.
Maybe "positive lookahead" "(?=" is incompatible with windev. I

Maybe you can can divide the problem. It's simplier to understand, easier to read and easier to modify, and i think it has the same process time:

MatchRegularExpression(MyPasswordString, "regConsant_Check_if_has_numbers")
MatchRegularExpression(MyPasswordString, "regConsant_Check_if_has_lowercase")
MatchRegularExpression(MyPasswordString, "regConsant_Check_if_has_uppercase")
MatchRegularExpression(MyPasswordString, "regConsant_Check_if_has_symbols")

IMHO.

Regards,
José Antonio.
#3
Posté le 16 avril 2014 - 19:29
Hi Danny,

Indeed, I had problems with regular expressions in WD too. The problem is that this is not a fully-flexible regular expression parser. MatchRegularExpression() really tries to "Match". If it does not absolutely match, it returns false, even if in fact, your regular expression could return totally good values.

I forgot to send them a report on this some weeks ago when I saw the problem. I'll do so and suggest them to implement a full-fledged regexp parser. That would be more than useful.

Best regards,
Alexandre Leclerc

PS: My regexp were all validating correctly on many websites that help building reg. expressions. But they were systematically not working in WD.
#4
Membre enregistré
962 messages
Posté le 30 avril 2014 - 01:35
hello Danny,
you can try to use the vbscript.regexp automation object like that :

sPassword is a string
MyRegexp is a object OLE "vbscript.regexp"
oMatches is a dynamic object OLE //MatchCollection
MyRegexp>>GLOBAL = True
// Pattern to test complexity of a password
// MyRegexp>>Pattern = "^.*(?=.{8,})(?=.*[a-z])(?=.*[A-Z])(?=.*[\W])(?=.*[\d]).*$" // Also OK
MyRegexp>>Pattern = "^(?:(?=.*[a-z])(?:(?=.*[A-Z])(?=.*[\d\W])|(?=.*\W)(?=.*\d))|(?=.*\W)(?=.*[A-Z])(?=.*\d)).{8,}$"
sPassword = "MyPassword"
oMatches = MyRegexp>>Execute(sPassword)
IF oMatches>>Count = 1 THEN Trace (sPassword," : Passord OK") ELSE Trace (sPassword," : Passord NOK")
sPassword = "MyPassword1?"
oMatches = MyRegexp>>Execute(sPassword)
IF oMatches>>Count = 1 THEN Trace (sPassword," : Passord OK") ELSE Trace (sPassword," : Passord NOK")


Friendly, J.P
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